in a quadrilateral ABCD, angle b is equal to angle d is equal to 90 degree ab is 7 cm AC is equal to 25 CM CD equals to 20 cm find the area of ABCD
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Step-by-step explanation:
here ADC isa rt triangle
AD=15
area of ADC=1/2*20*15=150
BC=24
area of ABC=84
are or quadrilateral=84+150=234
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