in a quadrilateral ABCD AO and bo are the bisector of angle A and Angle B respectively angle C is equal to 70 degree and Angle b is equal to 30 degree then angle aob is equal to
plz solve it step to step wise plz plz plz
it's answer is 50degree
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0
Answer:
i got it
Step-by-step explanation:
60°
Angles A+B+C+D =360
Therefore A+B = 240
In triangle AOB sum of angles is 180
A/2 + B/2 +O = 180
(A+B) /2 =120
O=60
Answered by
0
70+30=100
by theorem
100/2
50
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