Question

write the formula of TN and SN explaining all the terms​

Answer 1

Step-by-step explanation:

Sn = n/2 (2a + (n - 1) d)

Where,

n = no. of terms

a = first term

d = common difference

Answer 2

Sn = a + (a + d)+(a + 2d) + ... + (ℓ − 2d)+(ℓ − d) + ℓ. We have found the sum of an arithmetic progression in terms of its first and last terms, a and ℓ, and the number of terms n.
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