Question

In a quadrilateral ABCD as shown in figure ab//cd and AD perpendicular AB. if ab=18 ,dc=BC=13. FIND THE AREA OF QUADRILATERAL. hint- DRAW CE//AD so that CE perpendicular AB.EB=18m -13m=5m. In right angle triangle CEB,CE square=BC Square - BE square.​

Answer 1

The area is 186 sq m.

• CE || AD such that CE = AD
• As DC || AE, EB = AB - AE = 18 - 13  m = 5 m
• In triangle CEB, by Pythagoras theorem, CE^2 = CB^2 - BE^2 = 13^2 - 5^2 = 144 => CE = 12m
• hence, AD = CE = 12 m
• area of rect AECD = length * breadth = 13 * 12 = 156 sq m
• area of triangle CEB = 0.5 * height * base = 0.5 * 12 * 5 = 30 sq m
• therefore, area of quad ABCD = 156 + 30 = 186 sq m

Answer 2

Answer:

186m^2

Step-by-step explanation:

as we know trapezium is also a quadrilateral, we will be using the formula:

1/2*(a+b)*h

h=p

according to pythagoras theorem:

(h)^2=(p)^2+(b)^2

(13)^2=(p)^2+(5)^2

169 m=(p)^2+25 m

p^2=(169-25)m=144m

height^2=144m

height=√144m=12m

area=1/2*(13+18)m*12m

       =(31*6)m=186m

area of quadrilateral=186m^2

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