Question

In a Quadrilateral ABCD,in which the bisectors of Angle B and Angle C meet at O ,prove that Angle BOC=1/2(Angle A + Angle D)

Answer 1

Answer:

Angle BAO = 1/2 Angle A

Angle ABO = 1/2 Angle B

Angle AOB = 180–1/2(Angle A + Angle B)

Angle A +Angle B + Angle C + Angle D = 360°

Angle A + Angle B = 360-(Angle C+Angle D)

Angle AOB = 180–1/2 {360-(Angle C + Angle D)}

Angle AOB = 180–180 + 1/2 (Angle C +Angle D)

Angle AOB = 1/2 (Angle C+ AngleD)

Hence Proved

I hope it helped!!!

Answer 2

Answer:

here is your answer dear