In a quadrilateral ABCD, the angles A,B,C and D are in the ratio 1:2:3:4.Find the measure of the each angle of the quadrilateral
Answers
Answered by
499
Its easy, the simplest method is described below....
Add the ratios...1+2+3+4=10
Now find the angles as follows,
1st angle = (1/10)*360=36°
2nd angle =(2/10)*360=72°
3rd angle =(3/10)*360°=108°
4th angle =(4/10)*360°=144°
These are following angles.
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Add the ratios...1+2+3+4=10
Now find the angles as follows,
1st angle = (1/10)*360=36°
2nd angle =(2/10)*360=72°
3rd angle =(3/10)*360°=108°
4th angle =(4/10)*360°=144°
These are following angles.
Please mark as brainliest if you like my answer.
Answered by
237
Let the angles be 1y,2y,3y,4y.
1y+2y+3y+4y=360
10y=360
y=36
So 1y=36
2y=72
3y=108
4y=144
1y+2y+3y+4y=360
10y=360
y=36
So 1y=36
2y=72
3y=108
4y=144
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