In a Quadrilateral ABCD, the angles A, B, C and D are in the Ratio 1:2 : 4:5. Find the measure of each angle of the quadrilateral.
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Answer:
let the ratio be 1x, 2x, 3x and 4x.
1x +2x +3x +4x = 180°
10x = 180°
x = 180°/10
x = 18°
1x = 1×18 = 18°
2x = 2×18 = 36°
3x = 3×18= 54°
4x = 4×18 = 72°
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Given :-
In a Quadrilateral ABCD, the angles A, B, C and D are in the Ratio 1:2:4:5.
To Find :-
M easure of each angle of the quadrilateral.
Solution :-
Let the angles be x, 2x, 4x and 5x
Sum of all angles in a quadrilateral = 360
x + 2x + 4x + 5x = 360
12x = 360
x = 360/12
x = 30/1
x = 30
Therefore, Angles are
1x = 1(30) = 30°
2x = 2(30) = 60°
4x = 4(30) = 120°
5x = 5(30) = 150°
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