Math, asked by vandit4, 1 year ago

in a quadrilateral ABCD the line segment bisecting angle C and D meet at E prive that angle A+B =2angle CED

Answers

Answered by nova5

In triangle Aeb
diagnol of quadrilateral bisects it's angles
there for 1/2A+1/2B=AngleAEb
1/2(A+B)=angle AEB
A+B=2AEB

angle AEB=angle CED (vertically opposite angle)
therefore A+B=2Angle CED

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