in a quadrilateral CO and DO are the bisectors of angle C and angle D respectively prove that angle A+angle B=angle 2COD
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Angle DAB + Angle ABC +Angle BCD +Angle CDA =360degree
=> Angle DAB + Angle ABC + 2(Angle OCD + Angle ODC) =360degree
=> Angle DAB + Angle ABC +2(180degree - Angle COD) =360degree
=> Angle DAB + Angle ABC - 2Angle COD =360degree - 360degree
=> Angle DAB + Angle ABC =2Angle COD (Proved)
=> Angle DAB + Angle ABC + 2(Angle OCD + Angle ODC) =360degree
=> Angle DAB + Angle ABC +2(180degree - Angle COD) =360degree
=> Angle DAB + Angle ABC - 2Angle COD =360degree - 360degree
=> Angle DAB + Angle ABC =2Angle COD (Proved)
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its the shot of the answer with diagram so it will be easy to understand
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