In a quadrilateral CO anf DO are the bisectors of angle C and angle D respectively. Prove that angle A+angleB=2angleCOD
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In a quadrillteral abcd do and co are bisectors of c and d. Therefore in triangle cod..
Angle cod = 180-(1/2(d-c))
=Cod = 180-(1/2(360-(a+b)
Cod= 1/2(a+b)
2cod = a+b
Angle cod = 180-(1/2(d-c))
=Cod = 180-(1/2(360-(a+b)
Cod= 1/2(a+b)
2cod = a+b
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