in a quadrilateral if angle are arranged in ascending order when is next angle become twice the first find the last angle of quadrilateral
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the last angle of quadrilateral is 192
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Let the first angle of the quadrilateral be x
Then
2nd angle=2x
3rd=4x
4th=8x
Now by angle sum peoperty of quadrilateral
x+2x+4x+8x=360
15x=360
×=360/15
x=24
Last angle= 8×24=
= 192
Then
2nd angle=2x
3rd=4x
4th=8x
Now by angle sum peoperty of quadrilateral
x+2x+4x+8x=360
15x=360
×=360/15
x=24
Last angle= 8×24=
= 192
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