Math, asked by Hooj, 1 month ago

In a quadrilateral if sides 4 5 6 and x diagnols intersect each other at right angles find x
Please fast

Answers

Answered by xgliter85
0

Answer:

I623 323 1989

Pas000

Step-by-step explanation:

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Answered by vdsingh994
0

Answer:

ABCD is a parallelogram whose diagonals intersect each other at O with 90°.

so it's a rhombus as diagonals of rhombus interest each other at right angles.

diagonal1 (AC) = 6cm

diagonal 2(BD) = 8cm

OD = OB = 3cm each

OA = OC = 4cm each

Let, us take triangle AOB

it is a right angled triangle

=> (OA)² + (OB)² = (AB)²

=> (4)² + (3)² = (AB)²

=> 16 + 9 = (AB)²

=> 25 = (AB)²

=> \sqrt{25}

25

= AB

=> 5 = AB

So, AB = 5cm

AB = BC = CD = AD (all sides of rhombus are equal)

Each side of the parallelogram ABCD is 5cm

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