In a quadrilateral PQRS, if angle P=60°and angle Q: angle R: angle S=2:3:7,then angle 5=
Answers
Answered by
1
Step-by-step explanation:
Let the ABCD is a quadrilateral witch ∠A,∠B,∠Cand∠D in ratio 3:7:6:4
Sum of ratio 3+7+6+4=20
∠A+∠B+∠C+∠D=360
0
∴∠A=
20
3
×360=54
0
∴∠B=
20
7
×360=126
0
∴∠c=
20
6
×360=108
0
∴∠D=
20
4
×360=72
0
Then ABCD is a quadrilateral is trapezium
Similar questions