Math, asked by saloni12523, 8 months ago

In a quadrilateral PQRS,is (PQ+QR+RS)>(PS+QR)?

Answers

Answered by 2006aarthimani

1

Answer:

$03 - 2 = \div 3540 + 2 = 03gk \infty e \gamma \% \beta \beta \%$

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