In a quadrilateral PQRS, PQ = 5 cm, SR = 5 cm and PR = 6 cm, ∠QPR = 90, ∠PRS = 90
Find the area of the quadrilateral PQRS.
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Answer:
The area of the quadrilateral PQRS is 105cm².
Step-by-step explanation:
Given:
In a □PQRS,
- PQ = 5cm
- SR = 5cm
- PR = 6cm
- ∠QPR = 90°
- ∠PRS = 90°
To Find:
The area of □PQRS.
Solution:
To find the area of □PQRS = ?
Finding side PR = ?
Using Pythagoras theorem,
=> PR² = RQ² - PQ²
=> PR² = 17² - 8²
=> PR = 15cm
From the figure,
- SR is perpendicular to PR and PQ is perpendicular to PR.
=> Area of □PQRS = Area of ∆PQR + Area of ΔPSR ...(i)
=> Area of ΔPQR = 1/2 × PR × PQ ...(ii)
=> Area of ΔPSR = 1/2 × PR = RS ...(iii)
From the above equations (i), (ii) & (iii),
- Area of □PQRS = Area of ΔPQR + area of ΔPSR
- Area of □PQRS = 1/2 × PR × PQ + 1/2 × PR × RS ...(iv)
Now,
Equation (iv) can be written as:
=> Area of □PQRS = 1/2 × PR × (PQ+RS)
=> Area of □PQRS = 1/2 × 15 × (8+6)
=> Area of □PQRS = 1/2 × 15 × 14
=> Area of □PQRS = 105cm²
Therefore,
The area of the □PQRS is 105cm².
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