Question

In a quadrilateral the angle are x°(x-10°),(X+30°),2x°. find the angle?​

Answer 1

Step-by-step explanation:

We know that sum of all angle of a quadrilateral is 360⁰

x+x-10+x+30+2x=360⁰

5x+20=360⁰

5x=340⁰

x=340/5=68⁰

x=68⁰

x-10= 68-10 =58⁰

x+30=68+30 98⁰

2x= 2×68 = 136⁰

Answer 2

Step-by-step explanation:

Given that angles in the quadrilateral are

x° (x-10°) (x+30°) and 2x°

So, x+ x-10+ x+30+2x=360°

5x + 20= 360

5x = 360-20

5x = 340

x = 340/5

x = 68°

First angle = 68°.

Second angle = x-10 = 68-10 = 58°.

Third angle = x+ 30 = 68+30 = 98°.

Fourth angle = 2x = 2× 68 = 136°.

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