Question

in a quadrilateral the angles are in x degree x+10degree,x+20degree,x+30degree fin angles​

Answer 1

Answer:

sum of angles of a quadrilateral = 360°

so

x + (x + 10) + (x + 20) + (x + 30) = 360°

4x + 60 = 360°

4x = 360° - 60 = 300°

x = 300°/4 = 75°

so the angles are

x = 75°

(x + 10) = 75° + 10 = 85°

(x + 20) = 75° + 20 = 95°

(x + 30) = 75° + 30 = 105°

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