Question

In a quadrilateral,the angles are x degree,(x+10)degree,(x+20jdegrees,(x+30)degrees. Find the angles.

Answer 1

According to the formula :-

2(n-2) x 90degree = the sum of internal angles of a polygon,

The sum of angles of a quadrilateral is 360 degree.

So,

x + x + 10 + x + 20 + x + 30 = 360

=> 4x + 60 = 360

=> 4x = 300

=> x = 300/4. = 75

So, the value of x is 75 degree.


So, the angles are 75 degree, 85 degree, 95 degree and 105 degree.

Hope it helped :-)

Answer 2

In a quadrilateral, sum of all angles is always 360.
So, x +(x+10)+ (x+20)+(x+30) = 360
So, x+x+10+x+ 20 +x+30= 360
So, 4x+60 =360
So, 4x= 360-60
So, 4x = 300
So, x= 300/4
So x = 75

Angles are x =75, x+10 = 75+10= 85, x+20= 75+20=95, x+30 = 75+30= 105.


So, angles are 75, 85, 95 and 105