Question

In a quadrilateral triangle D is a point such that BD = 1/3 BC
PT 9 AD^2 = 7 AB ^2​

Answer 1

Answer:

$\Large{ \begin{tabular}{|c|c|c|c|c|c|} \cline{1-6} & \sf & \sf & \sf & \sf & \sf \\ \cline{1-6} S & F & V & E & F+V & E+2 \\ \cline{1-6} C & 6 & 8 & 12 & 14 & 14 \\ \cline{1-6} TP & 4 & 4 & 6 & 8 & 8 \\ \cline{1-6} TPR & 5 & 6 & 9 & 11 &11 \\ \cline{1 - 6} PSB & 5 & 5 & 8 & 10 & 10 \\ \cline{1-6} PRBS & 5 & 5 & 8 & 10 & 10 \\ \cline{1 - 6}\end{tabular}}$

Answer 2

Answer:

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