Question

In a queue, mr. x is fourteenth from the front and mr. y is seventeenth from the end, while mr. z is exactly in between mr. x and mr. y. if mr. x is ahead of mr. y and there are 48 persons in the queue, how many persons are there between mr. x and mr. z?

Answer 1

Total number of persons is 48.
Mr. x is at 14th position, and Mr.y is at 31st position. So number of persons in between is, from 15th to 30th member which is 16 members. And number of members including X and Y is 16+2 = 18. So middle person is at 18/2 th position, which is 9th position from Mr.X .
Now you've to count it this way,
1st - Mr.X (14th)
2nd - Mr.X +1(15th)
3rd - Mr.X +2(16th)
....
9th - Mr.X +8(22nd)

So you know Mr. Y is at 22nd position while Mr. X is at 14. So number of people in between is from 15th person to 21st person, i.e. 7 person.

Answer 2

Answer:8

Step-by-step explanation:

X is 14th from front

Y is 17th from end

There are 48 in total

Now let us find how many are there between x and y

48-(14+17)= 17

We know that z is exactly between x and y

Other than z there are 16 btw xand y

That is 8 between x and z and 8 btw z and y ( z is 9th among 17)

So answer is 8.