Question

In a race of 4000m around a circular ground of circum 1000m the fastest and slowest athletes meets first time 5 min after the starting of race . The speed of the all athletes remains constants over the race . The speed of the fatest is double of the slowest athletes. Than in how much time the athletes who wins the race will complete the race.

Answer 1

Answer:

10

Step-by-step explanation:

Given  

Let the speed of lowest be s m/min

Speed of fastest will be 2s m/min

We know that slowest moves x in 5 min

So x/s = 5 or x = 5s

For fastest he travels 1000 + x m to meet the slowest one.

1000 + x / 2s = 5

1000 + 5s = 10s

So s = 200 m/min for the slowest and for fastest it is 2s  

Now total time = 4000 / 400 = 10 min