In a rational number twice the numerator is two more than the denominator.If three is added to the numerator as well as the denominator,the new fraction is 2/3.Find the original number
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11
Let a be the numerator and b be the denominator.
given:
# 2a = 2+b
b = 2a - 2
# 3+a/3+b=2/3 (substitute b)
3 + a / 3 + 2a -2 = 2/3
3+a/1+2a=2/3 (cross multiply)
9+3a=2+4a
a=7
substitute a in b = 2a -2
b = 12.
given:
# 2a = 2+b
b = 2a - 2
# 3+a/3+b=2/3 (substitute b)
3 + a / 3 + 2a -2 = 2/3
3+a/1+2a=2/3 (cross multiply)
9+3a=2+4a
a=7
substitute a in b = 2a -2
b = 12.
Answered by
2
let the numerator be x
denominator = 2x-2
3 is added :-
Numerator= x+3
Denominator= 2x-2+3
=2x+1
x+3/2x+1=2/3
3(x+3)=2(2x+1)
3x+9=4x+2
3x-4x=2-9
-x=-7
x=7
Original Numerator = x = 7
Original Denominator = 2x-2
= 2(7)-2
= 14-2
= 12
Original Fraction = 7/12
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