Question

In a reaction, 2A → Products, the concentration of A decreases from 0.5 mol L−1 to 0.4 mol L−1 in 10 minutes. Calculate the rate during this interval?

Answer 1

Answer:

0.005 mol Litre^-1 min^-1.

Explanation:

Since from the question we get that the time is 10 minutes, initial concentration is 0.5 mol L−1  and final concentration is 0.4 mol L−1  hence to find the rate during that interval we know the rate formulae that.

Rate of the reaction is = - 1/2 change in concentration per unit time.

Which on putting the value will be -1/2*(0.4-0.5)/10 again this on solving we will get the value of the rate of the equation to be 0.005 mol Litre^-1 min^-1.

Answer 2

See the attachment...

HOPE THIS HELPS YOU!!!