Question

In a reaction, 5.3 g of sodium carbonate react with 6 g of ethanoic acid. The product was 2.2 g of carbon dioxide, 0.9 g water and 8.2 g of sodium ethanoate. Show that these observations are in agreement with the law of conservation of mass.​

Answer 1

Answer:

According to the question,

Na

2

CO

3

+CH

3

COOH→CO

2

+H

2

O+CH

3

COONa

Mass of reactants =5.3+6=11.3 gm

Mass of products =2.2+0.9+8.2=11.3 gm

This shows, that during a chemical reaction, the mass of reactant = mass of the product.

Hence, it shows the law of conservation of mass.

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Answer 2

Let us start from the reactant side

In the reactant side we have sodium carbonate and ethanoic acid

Mass of sodium carbonate=5.3g (given)

Mass of ethanoic acid=6g(given)

Now total mass before reaction that is mass of reactants = (5.3g + 6g) = 11.3g

Now let us check product side

Mass of carbon dioxide = 2.2g (given)

Mass of water = 0.9g (given)

Mass of sodium ethanoate = 8.2g (given)

Now total mass after reaction that is mass of products = (8.2g + 2.2g + 0.9g) = 11.3g

Conclusion

Total mass before reaction=total mass after reaction

Therefore the given observation is in agreement with the law of conservation of mass.