Question

In a reaction 5.3 g of sodium carbonate reacted with 6 g of ethanoic acid. The products were 2.2 g of carbon dioxide, 0.9 g water and 8.2 g of sodium ethanoate. Show that these observations are in agreement with the law of conservation of mass carbonate.​

Answer 1

Answer:

Explanation:

Na2 CO3 +CH3 COOH→CO  2  +H2 O+CH3 COONa

Mass of reactants =5.3+6=11.3 gm

Mass of products =2.2+0.9+8.2=11.3 gm

This shows, that during a chemical reaction, the mass of reactant = mass of the product.

Hence, it shows the law of conservation of mass.

Answer 2

Sodium carbonate + acetic acid → Sodium acetate + carbon dioxide + water

Solution :

Sodium carbonate + acetic acid → Sodium acetate + carbon dioxide + water

5.3g 6g 8.2g 2.2g 0.9g

As per the law of conservation of mass, the total mass of reactants must be equal to the total mass of products

As per the above reaction, LHS = RHS i.e., 5.3g + 6g = 2.2g + 0.9 g + 8.2 g = 11.3 g