Question

In a reaction 5.3 g of sodium carbonate reacted with 6 g of ethanoic acid. The products were 2.2 g of carbon dioxide, 0.9 g water and 8.2 g of sodium ethanoate. Show that these observations are in agreement with the law of conservation of mass carbonate.
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Answer 1

Answer:

Na2CO3 + CH3COOH ------> CO2 + H2O + NaCH3COO

Explanation:

Mass of reactants : 5.3 g + 6g = 11.3g

Mass of products: 2.2 g +0.9g + 8.2g = 11.3g

Mass of reactants = Mass of products.

So, the above reaction is in agreement with the law of conservation of mass.

Answer 2

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