Question

In a reaction, 5.3 g of sodium carbonate reacted with 6gof ethanoic

acid. The products were 2.2 gof carbon dioxide, 0.9 g water and 8.2 g

sodium ethanoate. Show that these observations are in agreement with

the law of conservation of mass, sodium carbonate+ cthanoic acid

sodium ethanoate +carbon dioxide +water.


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Answer 1

Question :-

• In a reaction, 5.3g of Sodium Carbonate reacted with 6g of ethanoic acid. The products were 2.2g of CO2, 0.9g of water and 8.2g of Sodium ethanoate. Show that these observations are in agreement with the law of conservation of mass, Sodium Carbonate + Ethanoic acid = Sodium ethanoate + Carbon dioxide + Water.

Solution :-

• Law of conservation of Mass States that "Mass is neither created, nor destroyed". i.e Mass of Reactants = Mass of products.

Reactants :-

• Mass of Sodium Carbonate = 5.3g
• Mass of ethanoic acid = 6g

Total mass of reactants

• = 5.3 + 6
• = 11.3g

Products :-

• Mass of Carbon Dioxide = 2.2g
• Mass of Water = 0.9g
• Mass of Sodium ethanoate = 8.2g

Total mass of products

• = 2.2 + 0.9 + 8.2
• = 3.1 + 8.2

=> 11.3g

• Here, Mass of Reactants = Mass of products
• •°• This reaction is in agreement with the law of conservation.

Answer 2

Answer:

Na

2

CO

3

+CH

3

COOH→CO

2

+H

2

O+CH

3

COONa

Mass of reactants =5.3+6=11.3 gm

Mass of products =2.2+0.9+8.2=11.3 gm

This shows, that during a chemical reaction, the mass of reactant = mass of the product.

Hence, it shows the law of conservation of mass.