In a reaction, 5.3g of sodium carbonate reacted with 6 g of acetic acid. The
products were 2.2 g of carbon dioxide, 0.9 g water and 8.2 g of sodium acetate.
Show that these observations are in agreement with the law of conservation of
mass
Answers
Answer:Heya !
Here is your answer ============================================================================
>> Mass of sodium carbonate = 5.3 g (given)
Mass of ethanoic acid = 6 g (given)
Mass of sodium ethanoate = 8.2 g (given)
Mass of Carbon dioxide = 2.2 g (given)
Mass of water = 0.9 g (given)
Now, total mass before the reaction = (5.3 + 6) g
= 11 . 3 g
And, total mass after the reaction = (8.2 + 2.2 + 0.9 ) g
= 11.3 g
total mass before the reaction = total mass after the reaction.
Hence, the given observations are in agreement with the law of conservation of mass.
Hope it helps !!! : )
Explanation:Pls mark the brainliest
Answer:
Explanation:
Sodium carbonate + acetic acid → Sodium acetate + carbon dioxide + water
Solution:
Sodium carbonate + acetic acid → Sodium acetate + carbon dioxide + water
5.3g 6g 8.2g 2.2g 0.9g
As per the law of conservation of mass, the total mass of reactants must be equal to the
total mass of
products
As per the above reaction, LHS = RHS i.e., 5.3g + 6g = 2.2g + 0.9 g + 8.2 g = 11.3 g
Hence the observations are in agreement with the law of conservation of mass.