Chemistry, asked by Anonymous, 8 months ago

In a reaction, 5.3g of sodium carbonate reacted with 6 g of acetic acid. The
products were 2.2 g of carbon dioxide, 0.9 g water and 8.2 g of sodium acetate.
Show that these observations are in agreement with the law of conservation of
mass

Answers

Answered by banerjeepriti56
5

Answer:Heya !

Here is your answer ============================================================================

>> Mass of sodium carbonate = 5.3 g (given)

Mass of ethanoic acid = 6 g (given)

Mass of sodium ethanoate = 8.2 g (given)

Mass of Carbon dioxide = 2.2 g (given)

Mass of water = 0.9 g (given)

Now, total mass before the reaction = (5.3 + 6) g

= 11 . 3 g

And, total mass after the reaction = (8.2 + 2.2 + 0.9 ) g

= 11.3 g

total mass before the reaction = total mass after the reaction.

Hence, the given observations are in agreement with the law of conservation of mass.

Hope it helps !!! : )

Explanation:Pls mark the brainliest

Answered by athiradamodaran21
1

Answer:

Explanation:

Sodium carbonate + acetic acid → Sodium acetate + carbon dioxide + water

Solution:

Sodium carbonate + acetic acid → Sodium acetate + carbon dioxide + water

5.3g 6g 8.2g 2.2g 0.9g

As per the law of conservation of mass, the total mass of reactants must be equal to the

total mass of

products

As per the above reaction, LHS = RHS i.e., 5.3g + 6g = 2.2g + 0.9 g + 8.2 g = 11.3 g

Hence the observations are in agreement with the law of conservation of mass.

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