Question

In a reaction 5.3g of sodium carbonate reacted with 6g of ethanoic acid . The products were 2.2g of CO2 , 0.9g of water & some sodium ethanoate . What is the expected weight of sodium carbonate .

Answer 1

let mass of sodium ethanoid be x
according to law of conservation of mass
mass if reactant=.mass of product
so,

mass if sodium carbonate +mass of ethanoid acid = mass of CO2+ mass of water+ mass of sodium ethanoid
5.3g + 6g+=2.2g+.9g+x
11.3g=3.1g +x
11.3g-3.1g=x
8.2g=x

Answer 2

Answer:

Heya !

Here is your answer ============================================================================

>> Mass of sodium carbonate = 5.3 g (given)

Mass of ethanoic acid = 6 g (given)

Mass of sodium ethanoate = 8.2 g (given)

Mass of Carbon dioxide = 2.2 g (given)

Mass of water = 0.9 g (given)

Now, total mass before the reaction = (5.3 + 6) g

= 11 . 3 g

And, total mass after the reaction = (8.2 + 2.2 + 0.9 ) g

= 11.3 g

total mass before the reaction = total mass after the reaction.

Hence, the given observations are in agreement with the law of conservation of mass.

Hope it helps !!! : )