Question

In a reaction a+b2=ab2 identify the limiting reagent when 2 mol of a are mixed with 3 mole of b2

Answer 1

Answer:'A' is the limiting reagent as 'A' combines with 'B' in 1:1 ratio

Explanation:

Answer 2

The limiting reagent in the given reaction is A

Explanation:

We are given:

Moles of A = 2 moles

Moles of $B_2$ = 3 moles

The given chemical equation follows:

$A+B_2\rightarrow AB_2$

By Stoichiometry of the reaction:

1 mole of A reacts with 1 mole of $B_2$

So, 2 moles of A will react with = $\frac{1}{1}\times 2=2mol$ of $B_2$

As, given amount of $B_2$ is more than the required amount. So, it is considered as an excess reagent.

Thus, A is considered as a limiting reagent because it limits the formation of product.

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