Chemistry, asked by Anjalibansal5790, 11 months ago

In a reaction betweem lead niterate and potassium iodide which product is in the form ofprecipitatr

Answers

Answered by singhajay025
2

Pb(NO3)2+2KI-->PbI2(ppt) + 2KNO3

Answered by kunal0912
1

Pb(NO3)2 + 2HCl ----------> PbCl2 + 2HNO3

PbCl2 + 2KI ----------> PbI2 + 2KCl

                           (yellow colour)

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