Chemistry, asked by Anjalibansal5790, 1 year ago

In a reaction betweem lead niterate and potassium iodide which product is in the form ofprecipitatr

Answers

Answered by singhajay025

2

Pb(NO3)2+2KI-->PbI2(ppt) + 2KNO3

Answered by kunal0912

1

Pb(NO3)2 + 2HCl ----------> PbCl2 + 2HNO3

PbCl2 + 2KI ----------> PbI2 + 2KCl

(yellow colour)

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