Question

In a reactor (V= 6 L) Fe and H2O were introduced at a determined temperature to reach the equilibrium: 3Fe(s) + 4H2O(g) D Fe3O4(s) + 4H2(g) In the equilibrium conditions, the amount of H2O(g) measured is 50 g. Knowing that the equilibrium constant of the process is Kc = 0.38, calculate the amount in grams of H2(g) at the equilibrium conditions.

Answer 1

Answer:

this question I did not understand