Question

In a rectangle ABCD, AB = 25 cm and BC = 15 cm. In what ratio does the bisector of ZC divide
AB?​

Answer 1

Answer:

2 : 3

Step-by-step explanation:

in a rectangle ABCD AB=25 cm BC=15 cm in what ratio bisector of angle C divide AB

Let say CE is  bisector of angle C

∠C = 90°

Bisector of ∠C = 45°

in Δ CEB

∠BCE = 45° & ∠B = 90°

=> Tan 45° =  BE /BC

=> 1 = BE/15

=> BE = 15 cm

AB = 25 cm   AB = AE + BE

=> 25 = AE + 15

=> AE = 10 cm

AE : BE :: 10 : 15

=> AE : BE :: 2 : 3

bisector of angle C divide AB in 2:3  ratio.

Answer 2

Answer:

2:3

Step-by-step explanation: