In a rectangle ABCD AB IS 20 and angle BAC IS 60 calculate side BC and diagonal AC and BD.
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ill tell you how to do it:
in triangleABC use tan60 = BC/AB
put value of AB and tan60 i.e. √3
youll get BC...and we know BC=AD and AB=DC......cheers!
in triangleABC use tan60 = BC/AB
put value of AB and tan60 i.e. √3
youll get BC...and we know BC=AD and AB=DC......cheers!
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