in a rectangle ABCD angle aob = 80 find angel ado and angle dca
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i a rectanle ABCD
angle AOB = 80°
the sum of all angles of a rectangle is 360°
therefore,
angle AOB+BOC+COD+AOD=360°
in a rectangle opposite angles are same
AOB=COD and BOC=AOD
the sum of interior angles are 180°
AOB+BOC=180°
80+BOC=180°
BOC=180-80
BOC=100°
AOD=100°
COD=80°
ADO =90°
DCA =AOD + COD
DCA= 100+80
DCA=180°
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