in a rectangle length is 2 meter more than breadth and its area 5 1/4 meter.find length and breadth
Answers
Answer:
Let breadth of the rectangle be 'b' cm.
So length of the rectangle will be 'b+2' cm.
Now
Perimeter =48
2(l+b)=48
2(b+2+b)=48
2b+2=24
2b=22
b=11 cm
l=b+2=13 cm
Then,
Area of the rectangle =lb
=13×11
=143 cm
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Answer:
The Length of the rectangle is 7/2
The Breath of the rectangle is 3/2
The Area of the rectangle is 21/4=5 1/4
Step-by-step explanation:
Area of a rectangle
A= l×b
length is 2 meter more than breadth
l=2+b===>1
A=5 1/4
Area is in mixed fraction
A=21/4
Substitute equation 1 in 2
A=l×b===>2
21/4=(2+b)(b)
21/4=2b+b²
b²+2b-21/4=0
a=1
b=2
c=-21/4
Product= a×c=-21/4
Sum=2
The values are -3/2 and 7/2
product=(-3/2)(7/2)=-21/4
Sum=(-3/2)+(7/2)=4/2=2
b²-3/2b+7/2b-21/4=0
b(b-3/2)+7/2(b-3/2)=0
(b-3/2)(b+7/2)=0
These are the Two values of the quadratic equation
b-3/2=0
b=3/2
b+7/2=0
b=-7/2
Negative value should be neglected
So, breadth of the rectangle is
b=3/2==>3
To find length
Substitute equation 3 in 1
l=2+b
l=2+3/2
l=(4+3)/2
l=7/2