In a rectangle PQRS ,the diagonals, bisect each other at 'O' prove that triangle POQ~= triangle ROS
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Hey fam!
Given,
PQRS is a rectangle.
O is the point of intersection of the diagonals.
To prove :- Triangle POQ congruent to Triangle ROS
Proof:-
In triangle POQ and triangle ROS,
PQ = SR{opposite sides of rectangle are equal}
angle OPQ = angle ORS
angle OQP = angle OSR
{alt. int. angles cause opposite sides of reatangle are parallel}
Therefore,
Triangle POQ congruent triangle ROS by ASA criterion.
Cheers!
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