Question

In a rectangle PQRS the diagonals bisect each other at 'o' prove that triangle POQ ~=triangle ROS​

Answer 1

prove=) PO=RO (BISECTOR GIVEN)

ANGLE POQ=ANGLE ROS (VERTICALLY OPPOSITE ANGLE)

OQ=OS (BISECTOR GIVEN)

SO, TRI. POQ~=TRI. ROS (USING SAS)

Answer 2

heya mate.. here's ur solution...

we know that in rectangle each angle is equal to 90degree...

so.. now... PQ parallel RS and PR is bisector... so..

IN Triangle POQ and triangle ROS

. /_OPQ =/_ORS and

/_OQP =/_OSR (alt int angles)

OP=OR(diagonals of a rectangle bisect each other)

so.. triangle POQ congruent triangle ROS (by AAS congruency)

hope this helps you...

thanks (in attachment ..drawing is not so good... SORRY for that)