in a regular pentagon ABCDE inscribed a circle find ratio between angle EDA and angle ADC
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In a regular pentagon ABCDE inscribed a circle find ratio between angle EDA and angle ADC
Step-by-step explanation:
Arc AE substends Angle AOE at the centre and Angle ADE at the remaining part of the circle.
Therefore Angle ADE = 1/2 ∆AOE
=1/2 *72°
=36°
∆ADC =∆ADB + ∆BDC
=36° +36° +72°
Therefore ∆ADE : ∆ADC =36:72
=1:2
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