Question

In a regular pentagon ABCDE what is the angle of BCE​

Answer 1

n-2*180

5-2*180

3*180

=540

Each angle=540/5=108

Therefore,<BCE =108

Answer 2

The angle of BCE​ is 108°.

Step-by-step explanation:

We know that,

The sum of all angles of regular polygon is 540°.

Let the angle of BCE​ = n

∴ (n - 2) × 180 = 540°

In a regular pentagon ,

Number of sides = 5

∴ Each angle =$\dfrac{540}{5}$

= 108°

∴ ∠BCE​ = 108°

Hence, the angle of BCE​ is 108°.