In a rhombus ABCD angles CBA =40 degrees find other angles?
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The angles of the rhombus ABCD are 40° , 40° , 140° and 140°.
In rhombus ABCD , ∠CBA = 40°, we have to find the other angles.
In rhombus opposite angles are equal.
Therefore, ∠CBA = ∠CDA and ∠BCD=∠BAD(Opposite angles of the rhombus are equal).
∠CBA + ∠CDA + ∠BCD + ∠BAD=360 (Sum of all angles of the quadrilateral is 360°)
40 + 40 + ∠BCD + ∠BAD=360
∠BCD + ∠BAD= 280
∠BAD + ∠BAD= 280
∠BAD= 140°.
Therefore ∠BCD =140°.
The other angles of the rhombus are 40° , 140° and 140°.
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