Question

In a rhombus ABCD diagonals AC and BD intersect at O and AC=6cm and

BD=8cm. Find the perimeter of ∆COD.​

Answer 1

Answer:

12c.m.

Step-by-step explanation:

AC=6c.m.

BD=8c.m.

perimeter of COD=?

triangle COD is aRight triangle.

So,here we can take OC as (b)=½ of AC=6/2=3c.m.

&(p)=OD=½of BD=8/2=4c.m.

then CD=(h)=√b²+p²

=√3²+4²

=√9+16

=√25

=5c.m.

Then Perimeter of COD=OC+OD+CD

=3c.m.+4c.m.+5c.m.

=12c.m.