Question

In a rhombus ABCD, find X,Y and Z. Hence, find the perimeter of the rhombus?

Answer 1

In Rhombus diagnols bisect each other at 90 degree.

x + 3 = 5

x = 2

12 = y + x

put value of x

12 = y + 2

y = 10

$z = \sqrt{12 {}^{2} + 5 {}^{2} }$

$z = \sqrt{144 + 25} = \sqrt{169}$

z = 13

Now all sides of rhombus all equal

Perimeter of rhombus = 4 × side

= 4 × 13

= 52


Thanks