In a rhombus ABCD if angle A = 60degree,AB=30cm.Find AC BD
Answers
Answered by
0
angle A =60°
let the intersection point of AC & BD be O.
angle OAB=30° [diagonals bisect vertex angles in a rhombus]
now angle AOB = 90° [ property of rhombus]
therefore ∆AOB is a right triangle with AB =30 cm
in the triangle, sin 30°= OB/AB
=> 1/2=OB/30
OB=30/2=15cm and therefore DB= 30cm
cos 30°= OA/AB
√3/2=OA/30
OA=30√3/2=15√3 and therefore AC= 30√3
let the intersection point of AC & BD be O.
angle OAB=30° [diagonals bisect vertex angles in a rhombus]
now angle AOB = 90° [ property of rhombus]
therefore ∆AOB is a right triangle with AB =30 cm
in the triangle, sin 30°= OB/AB
=> 1/2=OB/30
OB=30/2=15cm and therefore DB= 30cm
cos 30°= OA/AB
√3/2=OA/30
OA=30√3/2=15√3 and therefore AC= 30√3
Similar questions