Question

In a rhombus ABCD <ACB=40, then<ADB= ​

Answer 1

Answer:

∠COB=90

o

In △COB

∠COB+∠OBC+∠OBC=180

o

∠OBC=180

o

−90

o

−40

o

∠OBC=50

o

∠OBC=∠ADB ....[AD || BC]

∠ADB=50

o

Step-by-step explanation:

please mark me as brainliest and please follow