Question

In a rhombus ABCD the diagonals AC and and BD are 8 cm and 6 CM respectively please find the length of each side it it is very urgent please be quick​

Answer 1

Step-by-step explanation:

Length of each side of rhombus is

$= \frac{1}{2} \times \sqrt{ {d1}^{2} + {d2}^{2} }$

Here, d1 is diagonal 1 and d2 is diagonal 2.

$= \frac{1}{2} \times \sqrt{ {8}^{2} + {6}^{2} }$

$= \frac{1}{2} \times \sqrt{64 + 36}$

$\frac{1}{2} \times \sqrt{100}$

$= \frac{1}{2} \times 10$

$= 5 \: cm$

Therefore, the side of the rhombus is 5 cm

I hope it helps you. If you have any doubts, then don't hesitate to ask .

Answer 2

Answer:

Step-by-step explanation:

Solution :-

We know diagonals bisects at right angle

BY PYTHAGORAS THEOREM,

∴ In △AOD

AO²  +OD²=AD²

(3)² +(4)² =AD²

⇒AD=5cm

as AB = BC = CD = DA = 5 cm

{All sides of rhombus are equal}

refer the given attachment!!

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