In a rhombus if d1=16cm d2=12cm then the lenght of the side of the rhombus is
Answers
Answered by
34
Answer:
⇒ Let ABCD be the rhombus and AC and BD bisect at point O. AC = 16cm and BD = 12cm.
⇒ We know that the diagonals of rhombus bisect at right angles.
⇒ AO=
2
16
=8cm
⇒ BO=
2
12
=6cm
⇒ In right angled △AOB,
By using Pythagoras theorem,
⇒ AB
2
=AO
2
+BO
2
⇒ AB
2
=8
2
+6
2
⇒ AB
2
=64+36
⇒ AB
2
=100
⇒ AB=
100
⇒ AB=10cm
∴ Side of a rhombus is 10cm.
Answered by
36
Answer:
10cm.
Step-by-step explanation:
We know that, the diagonals of a rhombus are perpendicular bisector of each other.
Given, AC = 16 cm and BD = 12 cm [let]
∴ AO = 8cm, SO = 6cm
and ∠AOB = 90°
In right angled ∠AOB,
Bu pythagoras theorem. the value AB is 10cm.
See the image. Hope, it helps you.
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