Question

In a rhombus PQRS ,PQ =2y+10 and SR =5y+1. Find PQ

Answer 1

Hii There!!!

In the given question, PQRS is a parallelogram so its opposite sides are parallel and equal.
$\bf{i.e,\:PQ // RS\:and\:PQ = RS}$

So, it is given that...

PQ = 2y + 10 ----------1)

RS = 5y + 1 ----------2)

On equating equation 1 & equation 2 we get ;

2y + 10 = 5y + 1

= 2y - 5y = 1 - 10

= -3y = -9 [ negative sign will be cancelled out ]

= y = 9/3

=> y = 3

Therefore, $\boxed{y=3}$

On putting value of 'y' in equation 1) we get,

PQ = 2y + 10

=> 2 × 3 + 10

=> 6 + 10 = 16

Hence, $\boxed{length\:of\:PQ=16\:units}$

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