in a rhombus PQRS, PQ=4 cm, then the sum of the squares of the diagonals a)32cm b)64cm c)16cm d)8cm
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b is the answer I am sure
Coco324:
thank you bro .... I too know the answer is b but the question is how ....... can you plz save it?!!!!!
im loosing my mind just because of it
I meant solve it..!!
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Answer:
64 cm^2
Step-by-step explanation:
Sum of the squares of sides of rhombus= Sum of the squares of diagonals of a rhombus.
PS^2 + PQ^2 + QR^2 + RS^2 = PR^2 + QS^2
=4^2+4^2+4^2+4^2
therefore sum of the square of the diagonals = 64 cm^2
hope you understood
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