in a rhombus with side 5 cm if smaller diagonal is of length 6 cm then find of the length of the other diagonal
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Answer:
8 cm
Step-by-step explanation:
Let the other diagonal of the rhombus be x.
Since, diagonals of arhombus bisect each other,
and are perpendicular to each other.
Therefore,
applying pythagoras theorem.
(6/2)² +(x/2)² = 5²
=> 9 + (x/2)² = 25
=> (x²/4) = 16
=> x²= 64
=> x = 8
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